625^(2b)=(1/125)^-b

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Solution for 625^(2b)=(1/125)^-b equation: 



625^(2b)=(1/125)^-b

We move all terms to the left:

625^(2b)-((1/125)^-b)=0



Domain of the equation: 125)^-b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

625^2b-((+1/125)^-b)=0

We multiply all the terms by the denominator


625^2b*125)^-b)-((+1=0

Wy multiply elements

78125b^3+1=0

We do not support ebpression: b^3

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